![]() ![]() If you're going for the 150 it gets a little wonky and not a perfect 1, but oh well. (1 pump * 60 pressure = 60) / (10 engines * 6 consumption = 60) = 1 Basically if input/output = 1 then you're good. You can also use 2 pumps, 28 boilers, and 20 engines, etc. My reasoning is based off this Wiki page that states that one pump can fuel 10 Steam engines and 14 boilersġ pump on 1 pipe handles 10 engines, because it pumps 60 units per minute, and the engines consume 6 units a minute. If power is your concern, consider the following: This will start you off with only 2 offshore pumps and pumping stations far less, if you're needing to transport water so far. That being said, because the first 30 "pressure" drops off so quickly, it's probably best to just stick to 120 pressure. Those stations can't "increase" more water than they get in the first place through the single input pipe. If you're putting in a single pipe from a single pump into any of those stations, the maximum output will still be 60. In fact using the "pumping stations" from the other answer literally won't even work if your input isn't as high as your desired output. Therefore it will take more than just 1 pump to achieve full capacity.ġ50/60 = 2.5, or 3 minimum pumps to achieve 150 "pressure". 60 units of water per second." Source: Offshore PumpĪs we know, pipes can handle up to 150 units of water per second. that answer doesn't exactly apply to this specific question? :) ![]()
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